Today, in my calculus class, we encountered the function e−x2 e x 2, and I was told that it was not integrable. I was very surprised. Is there really no way to find the integral of e−x2 e x 2? Graphing …

The integral which you describe has no closed form which is to say that it cannot be expressed in elementary functions. For example, you can express $\int x^2 \mathrm {d}x$ in elementary functions …

What is the integral of $$\int_ {-\infty}^ {\infty}e^ {-x^2/2}dx\,?$$ My working is here: = $-e^ (-1/2x^2)/x$ from negative infinity to infinity. What is the value of this?

0 There is is no elementary function for the indefinite gaussian integral. The best you can do is represent it through a Taylor series, and then compute it numerically with the desired precision. Yet calculating …

Jan 15, 2014 · Hints For the first one, use a substitution. For the second one, integrate by parts.

Aug 26, 2015 · Then take square roots, noting that your integral must be positive. The function $x^2e^ {-x^2}$ has no elementary antiderivative, so usual techniques like integration by parts or by …

May 21, 2020 · 14 Interestingly, the definite integral $$ \int_0^\infty e^ {-x^n}dx $$ can be evaluated for any $n>0$, and is equal to $\Gamma ( (n+1)/n)$.

Sep 27, 2019 · Calculate the integral $\int e^ {\sin x}\,dx$ Ask Question Asked 8 years, 8 months ago Modified 6 years, 2 months ago

Jan 19, 2015 · I don't know how to evaluate it. I know there is one method using the gamma function. BUT I want to know the solution using a calculus method like polar coordinates. $$\\int_{ …

Nov 11, 2015 · How does one evaluate $$\\int_{-\\infty}^{\\infty} e^{ix^2} dx$$ I know the trick how to evaluate $\\int_{-\\infty}^{\\infty} e^{-x^2}dx$ but trying to apply it here I get a limit which does not …